"Cannot record in this recording setting" on fast SD

[ErikVos]

Hi, I want to shoot a video in "XAVC HS 4K" or "XAVC S 4K" in S&Q modus on a "SanDisk Extreme PRO 128GB card" with 200MB/s (SDXC). But I get a message:
"Cannot record in this recording setting. Switch to a memory card higher then SDXC V60 or change the video file Format."
Which I think is already in the camera?! Freshly formatted. I have no problems if I shoot the video in "XAVC HS 4K" format on the same card and in video modus! The problem seems to be the S&Q modus, but I am filming in the "slow" modus: Frame Rate 6fps (PAL 150M 4:2:0 10 bit)
Please, who knows what goes wrong? Thanks.

[FunWithCameras]

It looks like the message is telling you that you need a card faster than v60 - that could be a v90 or faster. These ratings tell the camera what the sustained write speed is. A card can be labelled as 200Mb/s but that may be its maximum READ speed. It’s sustained WRITE speed may be much lower.

There is at least one Sandisk Extreme Pro SDXC card labelled 200Mb/s which is only a v30, not even a v60. It has a read speed up to 200MB/s, but its write speed is only 90MB/s.

That could be your problem.

[ErikVos]

4 hours ago, FunWithCameras said:

It looks like the message is telling you that you need a card faster than v60 - that could be a v90 or faster. These ratings tell the camera what the sustained write speed is. A card can be labelled as 200Mb/s but that may be its maximum READ speed. It’s sustained WRITE speed may be much lower.

There is at least one Sandisk Extreme Pro SDXC card labelled 200Mb/s which is only a v30, not even a v60. It has a read speed up to 200MB/s, but its write speed is only 90MB/s.

That could be your problem.

Thanks! Indeed that could be the problem. Never thought that the write speed could be that bad. And still don't understand why shooting with 6 frames per second is not possible on a card like this, while I can shoot 25 frames per second on the same card. Probably Sony does not make a diffrence between "Slow" & "Quick".
Thanks for your answer!